40x-56x^2=0

Solution for 40x-56x^2=0 equation:

40x-56x^2=0

a = -56; b = 40; c = 0;
Δ = b2-4ac
Δ = 402-4·(-56)·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-40}{2*-56}=\frac{-80}{-112}
=5/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+40}{2*-56}=\frac{0}{-112}
=0
$